3x2+10x=6x-1

Solution for 3x2+10x=6x-1 equation:

3x^2+10x=6x-1

We move all terms to the left:

3x^2+10x-(6x-1)=0

We get rid of parentheses

3x^2+10x-6x+1=0

We add all the numbers together, and all the variables

3x^2+4x+1=0

a = 3; b = 4; c = +1;
Δ = b2-4ac
Δ = 42-4·3·1
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2}{2*3}=\frac{-6}{6}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2}{2*3}=\frac{-2}{6}
=-1/3
$