3x2+11x+10=10

Solution for 3x2+11x+10=10 equation:

3x^2+11x+10=10

We move all terms to the left:

3x^2+11x+10-(10)=0

We add all the numbers together, and all the variables

3x^2+11x=0

a = 3; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·3·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*3}=\frac{-22}{6}
=-3+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*3}=\frac{0}{6}
=0
$