If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3x^2+13x+10=0
a = 3; b = 13; c = +10;
Δ = b2-4ac
Δ = 132-4·3·10
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-7}{2*3}=\frac{-20}{6} =-3+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+7}{2*3}=\frac{-6}{6} =-1 $
| 6x2-2x-8=0 | | 3x2+13x+-10=0 | | a²=64 | | 7x^2-1-(2x+1)(3x-2)=x^2 | | 8x+3=10x-4 | | 10(x+2)=6x+15 | | 3(2x-10)=4x-80 | | 7x-19=5x+49 | | 6x=2x=40 | | q/4+2=-1 | | 224x=0 | | x^2+30x+10800=0 | | X2+6x+10=0 | | P^2+6p-1=8 | | x2+6x+16=0 | | 5+u4=36 | | x^2=(6x-2)÷9 | | 4^(x-3)=4^x-252 | | P2+6p-1=8 | | x^2=(6x-2)÷9. | | 150y=6y² | | 4^x-3=4^x-252 | | n(4n-1)-5=0 | | 3.2(d)=2d-5 | | (2x-5)(x+3)=7x+21 | | 6x67=100 | | 6x²-7x-5=0 | | 4.5x+90=117 | | -z^2+45+12z=0 | | (3x+1)/5=-1 | | x²+19x-42=0 | | 3+3/5x=0 |