3x2+13x-4=0

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Solution for 3x2+13x-4=0 equation:



3x^2+13x-4=0
a = 3; b = 13; c = -4;
Δ = b2-4ac
Δ = 132-4·3·(-4)
Δ = 217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{217}}{2*3}=\frac{-13-\sqrt{217}}{6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{217}}{2*3}=\frac{-13+\sqrt{217}}{6} $

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