3x2+18x+36x=9

Solution for 3x2+18x+36x=9 equation:

3x^2+18x+36x=9

We move all terms to the left:

3x^2+18x+36x-(9)=0

We add all the numbers together, and all the variables

3x^2+54x-9=0

a = 3; b = 54; c = -9;
Δ = b2-4ac
Δ = 542-4·3·(-9)
Δ = 3024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3024}=\sqrt{144*21}=\sqrt{144}*\sqrt{21}=12\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-12\sqrt{21}}{2*3}=\frac{-54-12\sqrt{21}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+12\sqrt{21}}{2*3}=\frac{-54+12\sqrt{21}}{6}
$