If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3x^2+19x-14=0
a = 3; b = 19; c = -14;
Δ = b2-4ac
Δ = 192-4·3·(-14)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-23}{2*3}=\frac{-42}{6} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+23}{2*3}=\frac{4}{6} =2/3 $
| 180-x=280-3x | | 2(7x-3)=4(7-2x)+5x | | 10+20=-3(2x+10) | | X=0.5x(x+2) | | 5f+19=2(3f+1) | | 7x-11=9x-23 | | x+4.3=10* | | 10-3e=15+2e | | 10-2/3x=8 | | -2(3k-4)-(k+3)=-9 | | a/15=24 | | 5(2x+8)=-45+65 | | 8i=12 | | 4d-40=68-2d | | 3(2x6+5)=39 | | -15=-8m | | 3x12=-12+5x | | 8a(1+5a)+4(3a11)=20 | | 4(3x-1)²=100 | | 3c+12=9c-108 | | 17x-46=16x-29 | | 2(5x+6)=-39+31 | | 8m-12=19+2(5m+9) | | 2j+32=24 | | x−14=27,x= | | x2–3x+16=7x | | 18x=1,008 | | 5b+15=15b+65 | | -5(t+3)=-30 | | 5y-16=11y+26 | | 2−35–√=x | | .5(6x+8)=2x=4=x |