3x2+23x=0

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Solution for 3x2+23x=0 equation: 



3x^2+23x=0

a = 3; b = 23; c = 0;
Δ = b2-4ac
Δ = 232-4·3·0
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-23}{2*3}=\frac{-46}{6}
=-7+2/3
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+23}{2*3}=\frac{0}{6}
=0
$

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