3x2+25x=-50

Solution for 3x2+25x=-50 equation:

3x^2+25x=-50

We move all terms to the left:

3x^2+25x-(-50)=0

We add all the numbers together, and all the variables

3x^2+25x+50=0

a = 3; b = 25; c = +50;
Δ = b2-4ac
Δ = 252-4·3·50
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-5}{2*3}=\frac{-30}{6}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+5}{2*3}=\frac{-20}{6}
=-3+1/3
$