3x2+27x=30

Solution for 3x2+27x=30 equation:

3x^2+27x=30

We move all terms to the left:

3x^2+27x-(30)=0

a = 3; b = 27; c = -30;
Δ = b2-4ac
Δ = 272-4·3·(-30)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-33}{2*3}=\frac{-60}{6}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+33}{2*3}=\frac{6}{6}
=1
$