3x2+30x-90000=0

Solution for 3x2+30x-90000=0 equation:

3x^2+30x-90000=0

a = 3; b = 30; c = -90000;
Δ = b2-4ac
Δ = 302-4·3·(-90000)
Δ = 1080900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1080900}=\sqrt{900*1201}=\sqrt{900}*\sqrt{1201}=30\sqrt{1201}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-30\sqrt{1201}}{2*3}=\frac{-30-30\sqrt{1201}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+30\sqrt{1201}}{2*3}=\frac{-30+30\sqrt{1201}}{6}
$