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3x^2+33x+30=0
a = 3; b = 33; c = +30;
Δ = b2-4ac
Δ = 332-4·3·30
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-27}{2*3}=\frac{-60}{6} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+27}{2*3}=\frac{-6}{6} =-1 $
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