3x2+36x+49-8x=0

Solution for 3x2+36x+49-8x=0 equation:

3x^2+36x+49-8x=0

We add all the numbers together, and all the variables

3x^2+28x+49=0

a = 3; b = 28; c = +49;
Δ = b2-4ac
Δ = 282-4·3·49
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-14}{2*3}=\frac{-42}{6}
=-7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+14}{2*3}=\frac{-14}{6}
=-2+1/3
$