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3x^2+36x+81=0
a = 3; b = 36; c = +81;
Δ = b2-4ac
Δ = 362-4·3·81
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-18}{2*3}=\frac{-54}{6} =-9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+18}{2*3}=\frac{-18}{6} =-3 $
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