3x2+3x-1395=0

Solution for 3x2+3x-1395=0 equation:

3x^2+3x-1395=0

a = 3; b = 3; c = -1395;
Δ = b2-4ac
Δ = 32-4·3·(-1395)
Δ = 16749
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{16749}=\sqrt{9*1861}=\sqrt{9}*\sqrt{1861}=3\sqrt{1861}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3\sqrt{1861}}{2*3}=\frac{-3-3\sqrt{1861}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3\sqrt{1861}}{2*3}=\frac{-3+3\sqrt{1861}}{6}
$