3x2+47x=30

Solution for 3x2+47x=30 equation:

3x^2+47x=30

We move all terms to the left:

3x^2+47x-(30)=0

a = 3; b = 47; c = -30;
Δ = b2-4ac
Δ = 472-4·3·(-30)
Δ = 2569
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(47)-\sqrt{2569}}{2*3}=\frac{-47-\sqrt{2569}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(47)+\sqrt{2569}}{2*3}=\frac{-47+\sqrt{2569}}{6}
$