3x2+4=2x+53x2+4=2x+5

Solution for 3x2+4=2x+53x2+4=2x+5 equation:

3x^2+4=2x+53x^2+4=2x+5

We move all terms to the left:

3x^2+4-(2x+53x^2+4)=0

We get rid of parentheses

3x^2-53x^2-2x-4+4=0

We add all the numbers together, and all the variables

-50x^2-2x=0

a = -50; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-50)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-50}=\frac{0}{-100}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-50}=\frac{4}{-100}
=-1/25
$