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3x^2+4=x-1
We move all terms to the left:
3x^2+4-(x-1)=0
We get rid of parentheses
3x^2-x+1+4=0
We add all the numbers together, and all the variables
3x^2-1x+5=0
a = 3; b = -1; c = +5;
Δ = b2-4ac
Δ = -12-4·3·5
Δ = -59
Delta is less than zero, so there is no solution for the equation
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