3x2+4x-1900=0

Solution for 3x2+4x-1900=0 equation:

3x^2+4x-1900=0

a = 3; b = 4; c = -1900;
Δ = b2-4ac
Δ = 42-4·3·(-1900)
Δ = 22816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{22816}=\sqrt{16*1426}=\sqrt{16}*\sqrt{1426}=4\sqrt{1426}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{1426}}{2*3}=\frac{-4-4\sqrt{1426}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{1426}}{2*3}=\frac{-4+4\sqrt{1426}}{6}
$