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3x^2+4x-3=x2-21+4x
We move all terms to the left:
3x^2+4x-3-(x2-21+4x)=0
We add all the numbers together, and all the variables
3x^2-(+x^2+4x-21)+4x-3=0
We get rid of parentheses
3x^2-x^2-4x+4x+21-3=0
We add all the numbers together, and all the variables
2x^2+18=0
a = 2; b = 0; c = +18;
Δ = b2-4ac
Δ = 02-4·2·18
Δ = -144
Delta is less than zero, so there is no solution for the equation
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