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3x^2+4x^2=252
We move all terms to the left:
3x^2+4x^2-(252)=0
We add all the numbers together, and all the variables
7x^2-252=0
a = 7; b = 0; c = -252;
Δ = b2-4ac
Δ = 02-4·7·(-252)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7056}=84$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-84}{2*7}=\frac{-84}{14} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+84}{2*7}=\frac{84}{14} =6 $
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