3x2+50x-75000=0

Solution for 3x2+50x-75000=0 equation:

3x^2+50x-75000=0

a = 3; b = 50; c = -75000;
Δ = b2-4ac
Δ = 502-4·3·(-75000)
Δ = 902500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{902500}=950$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-950}{2*3}=\frac{-1000}{6}
=-166+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+950}{2*3}=\frac{900}{6}
=150
$