If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3x^2+5x+1=97
We move all terms to the left:
3x^2+5x+1-(97)=0
We add all the numbers together, and all the variables
3x^2+5x-96=0
a = 3; b = 5; c = -96;
Δ = b2-4ac
Δ = 52-4·3·(-96)
Δ = 1177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{1177}}{2*3}=\frac{-5-\sqrt{1177}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{1177}}{2*3}=\frac{-5+\sqrt{1177}}{6} $
| 2(p+5)1(9+p)=-3 | | 1/2/8=x/16 | | Y=5x=3 | | 42x-14=0 | | 3x2-5x=22 | | √5x=x+8 | | k+11=17 | | (2x-40)=(3x-85) | | 10+3x=2(3+4×)+5 | | 2(1-x)-3=3(2x+1)+20 | | 3x=16=1-2x | | (u)(4u-24)=-36 | | 17.7+(10)6=d | | 5x+200=3500 | | 4x+2=2x-7 | | (u)(4u-24)=36 | | 3x-20=5x-32 | | 6(3x+7)-2x=-6 | | 1=p4+4 | | 1=p4+ 4 | | 5x+0,2=3,5 | | 11(v+4)-2v=3(3v+1)-12 | | -4m=-1/3 | | 5.4x=2.16 | | 2k+8=2 | | 3p+12=5p+6 | | 18x-5x+2=(x-3)-1 | | 7-2u=13 | | 2x÷9=-8 | | -50=5(n-3) | | -4(-6y+5)-6y=3(y-8)-2 | | .2×5z=0 |