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3x^2+5x-2=2x-5
We move all terms to the left:
3x^2+5x-2-(2x-5)=0
We get rid of parentheses
3x^2+5x-2x+5-2=0
We add all the numbers together, and all the variables
3x^2+3x+3=0
a = 3; b = 3; c = +3;
Δ = b2-4ac
Δ = 32-4·3·3
Δ = -27
Delta is less than zero, so there is no solution for the equation
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