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3x^2+5x-2=x+2
We move all terms to the left:
3x^2+5x-2-(x+2)=0
We get rid of parentheses
3x^2+5x-x-2-2=0
We add all the numbers together, and all the variables
3x^2+4x-4=0
a = 3; b = 4; c = -4;
Δ = b2-4ac
Δ = 42-4·3·(-4)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-8}{2*3}=\frac{-12}{6} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+8}{2*3}=\frac{4}{6} =2/3 $
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