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3x^2+60x+300=0
a = 3; b = 60; c = +300;
Δ = b2-4ac
Δ = 602-4·3·300
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-60}{6}=-10$
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