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3x^2+6x=-3
We move all terms to the left:
3x^2+6x-(-3)=0
We add all the numbers together, and all the variables
3x^2+6x+3=0
a = 3; b = 6; c = +3;
Δ = b2-4ac
Δ = 62-4·3·3
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-6}{6}=-1$
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