3x2+72=33x

Solution for 3x2+72=33x equation:

3x^2+72=33x

We move all terms to the left:

3x^2+72-(33x)=0

a = 3; b = -33; c = +72;
Δ = b2-4ac
Δ = -332-4·3·72
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-15}{2*3}=\frac{18}{6}
=3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+15}{2*3}=\frac{48}{6}
=8
$