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3x^2+8=2x-3
We move all terms to the left:
3x^2+8-(2x-3)=0
We get rid of parentheses
3x^2-2x+3+8=0
We add all the numbers together, and all the variables
3x^2-2x+11=0
a = 3; b = -2; c = +11;
Δ = b2-4ac
Δ = -22-4·3·11
Δ = -128
Delta is less than zero, so there is no solution for the equation
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