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3x^2+8x-203=0
a = 3; b = 8; c = -203;
Δ = b2-4ac
Δ = 82-4·3·(-203)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-50}{2*3}=\frac{-58}{6} =-9+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+50}{2*3}=\frac{42}{6} =7 $
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