3x2+92x-7200=0

Solution for 3x2+92x-7200=0 equation:

3x^2+92x-7200=0

a = 3; b = 92; c = -7200;
Δ = b2-4ac
Δ = 922-4·3·(-7200)
Δ = 94864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{94864}=308$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(92)-308}{2*3}=\frac{-400}{6}
=-66+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(92)+308}{2*3}=\frac{216}{6}
=36
$