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3x^2-17x+22=0
a = 3; b = -17; c = +22;
Δ = b2-4ac
Δ = -172-4·3·22
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-5}{2*3}=\frac{12}{6} =2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+5}{2*3}=\frac{22}{6} =3+2/3 $
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