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3x^2-18x+5=180
We move all terms to the left:
3x^2-18x+5-(180)=0
We add all the numbers together, and all the variables
3x^2-18x-175=0
a = 3; b = -18; c = -175;
Δ = b2-4ac
Δ = -182-4·3·(-175)
Δ = 2424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2424}=\sqrt{4*606}=\sqrt{4}*\sqrt{606}=2\sqrt{606}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{606}}{2*3}=\frac{18-2\sqrt{606}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{606}}{2*3}=\frac{18+2\sqrt{606}}{6} $
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