3x2-1938X+447=0

Solution for 3x2-1938X+447=0 equation:

3x^2-1938x+447=0

a = 3; b = -1938; c = +447;
Δ = b2-4ac
Δ = -19382-4·3·447
Δ = 3750480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3750480}=\sqrt{144*26045}=\sqrt{144}*\sqrt{26045}=12\sqrt{26045}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1938)-12\sqrt{26045}}{2*3}=\frac{1938-12\sqrt{26045}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1938)+12\sqrt{26045}}{2*3}=\frac{1938+12\sqrt{26045}}{6}
$