3x2-19x+40=0

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Solution for 3x2-19x+40=0 equation: 



3x^2-19x+40=0

a = 3; b = -19; c = +40;
Δ = b2-4ac
Δ = -192-4·3·40
Δ = -119
Delta is less than zero, so there is no solution for the equation

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