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3x^2-1=134
We move all terms to the left:
3x^2-1-(134)=0
We add all the numbers together, and all the variables
3x^2-135=0
a = 3; b = 0; c = -135;
Δ = b2-4ac
Δ = 02-4·3·(-135)
Δ = 1620
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1620}=\sqrt{324*5}=\sqrt{324}*\sqrt{5}=18\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{5}}{2*3}=\frac{0-18\sqrt{5}}{6} =-\frac{18\sqrt{5}}{6} =-3\sqrt{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{5}}{2*3}=\frac{0+18\sqrt{5}}{6} =\frac{18\sqrt{5}}{6} =3\sqrt{5} $
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