If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3x^2-1x-200=0
a = 3; b = -1; c = -200;
Δ = b2-4ac
Δ = -12-4·3·(-200)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-49}{2*3}=\frac{-48}{6} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+49}{2*3}=\frac{50}{6} =8+1/3 $
| 3x-15+3x-15=24 | | 10.216+c=-12.014 | | -(-4y-2)=-30 | | 9b+90=11 | | 2x^2+240=88x | | b+26/7=8 | | 14(d-30)=-196 | | 0.4x=12×0.4 | | 3z+4z=5 | | 2y-3(4y-5)=35 | | –23x=–12. | | (k-9)^4=4 | | 8(5n-1)=-8(-8n-10)-2n | | v-93/6=1 | | 2X+1y=51 | | x+7/8=2x-7/6 | | -15.3=-7.5d+55.2 | | 7-4b=-61 | | 18=-5b+8b-9 | | 26=4a-12 | | 45=w+14/0.6 | | 4(s+1.5)=(2•4s)-10 | | 2(x^2+1)+5x=0 | | 3(d-56)=75 | | (n-7)=(n+8) | | z/4-2=3 | | 40=8(u-88) | | (n+7)=(n+8) | | n+4+n+4=3n-1 | | c^-6c=0 | | -47=13+3c | | -8u=u+5 |