3x2-2(x-4)=X-12

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Solution for 3x2-2(x-4)=X-12 equation: 



3x^2-2(x-4)=x-12

We move all terms to the left:

3x^2-2(x-4)-(x-12)=0

We multiply parentheses

3x^2-2x-(x-12)+8=0

We get rid of parentheses

3x^2-2x-x+12+8=0

We add all the numbers together, and all the variables

3x^2-3x+20=0

a = 3; b = -3; c = +20;
Δ = b2-4ac
Δ = -32-4·3·20
Δ = -231
Delta is less than zero, so there is no solution for the equation

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