3x2-24x-3840=0

Solution for 3x2-24x-3840=0 equation:

3x^2-24x-3840=0

a = 3; b = -24; c = -3840;
Δ = b2-4ac
Δ = -242-4·3·(-3840)
Δ = 46656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{46656}=216$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-216}{2*3}=\frac{-192}{6}
=-32
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+216}{2*3}=\frac{240}{6}
=40
$