3x2-25x+36=8

Solution for 3x2-25x+36=8 equation:

3x^2-25x+36=8

We move all terms to the left:

3x^2-25x+36-(8)=0

We add all the numbers together, and all the variables

3x^2-25x+28=0

a = 3; b = -25; c = +28;
Δ = b2-4ac
Δ = -252-4·3·28
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-17}{2*3}=\frac{8}{6}
=1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+17}{2*3}=\frac{42}{6}
=7
$