If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3x^2-28x+9=0
a = 3; b = -28; c = +9;
Δ = b2-4ac
Δ = -282-4·3·9
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-26}{2*3}=\frac{2}{6} =1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+26}{2*3}=\frac{54}{6} =9 $
| -7b-2=4-9b | | -2x2+20x-46=0 | | 21v=168 | | .6667x-6=18 | | 30=t/25 | | 10+5g=-g-8 | | 30=t25 | | -9-y=-4y+9 | | 17=t−42 | | 7x+40=-2 | | 7x2-6x+2=0 | | b+38=61 | | -6+2g=7g+9 | | -2m-3=-10-9m | | 7x2-22x+3=0 | | r+6=6+r | | 7x2-35=0 | | 0.5x+3=-9 | | 5(3x+9)-2x=15x-2(x-5)+10 | | -4c+9=9-4c | | -10-6h=-10-5h | | 10-8z=-8z+10 | | -4(2x-8)=5+7(-2x+7) | | -8f-8=-8f-9 | | -7q+6=6-7q | | 7(4x-2)=2(-3x-8)-24 | | 2(x+16=50 | | -2t+6=3-2t | | 2+(4x)/3(-7)=1 | | 5-h=-h | | x/15+16=17 | | 2f-4=3f+1 |