3x2-2x+1=4x+28,72

Solution for 3x2-2x+1=4x+28,72 equation:

3x^2-2x+1=4x+28.72

We move all terms to the left:

3x^2-2x+1-(4x+28.72)=0

We get rid of parentheses

3x^2-2x-4x-28.72+1=0

We add all the numbers together, and all the variables

3x^2-6x-27.72=0

a = 3; b = -6; c = -27.72;
Δ = b2-4ac
Δ = -62-4·3·(-27.72)
Δ = 368.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-\sqrt{368.64}}{2*3}=\frac{6-\sqrt{368.64}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+\sqrt{368.64}}{2*3}=\frac{6+\sqrt{368.64}}{6}
$