3x2-300x+5000=0

Solution for 3x2-300x+5000=0 equation:

3x^2-300x+5000=0

a = 3; b = -300; c = +5000;
Δ = b2-4ac
Δ = -3002-4·3·5000
Δ = 30000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{30000}=\sqrt{10000*3}=\sqrt{10000}*\sqrt{3}=100\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-300)-100\sqrt{3}}{2*3}=\frac{300-100\sqrt{3}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-300)+100\sqrt{3}}{2*3}=\frac{300+100\sqrt{3}}{6}
$