3x2-35=16x

Solution for 3x2-35=16x equation:

3x^2-35=16x

We move all terms to the left:

3x^2-35-(16x)=0

a = 3; b = -16; c = -35;
Δ = b2-4ac
Δ = -162-4·3·(-35)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-26}{2*3}=\frac{-10}{6}
=-1+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+26}{2*3}=\frac{42}{6}
=7
$