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3x^2-35x+88=0
a = 3; b = -35; c = +88;
Δ = b2-4ac
Δ = -352-4·3·88
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-13}{2*3}=\frac{22}{6} =3+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+13}{2*3}=\frac{48}{6} =8 $
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