3x2-36x+10=0

Solution for 3x2-36x+10=0 equation:

3x^2-36x+10=0

a = 3; b = -36; c = +10;
Δ = b2-4ac
Δ = -362-4·3·10
Δ = 1176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1176}=\sqrt{196*6}=\sqrt{196}*\sqrt{6}=14\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-14\sqrt{6}}{2*3}=\frac{36-14\sqrt{6}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+14\sqrt{6}}{2*3}=\frac{36+14\sqrt{6}}{6}
$