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3x^2-37x+85=0
a = 3; b = -37; c = +85;
Δ = b2-4ac
Δ = -372-4·3·85
Δ = 349
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-\sqrt{349}}{2*3}=\frac{37-\sqrt{349}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+\sqrt{349}}{2*3}=\frac{37+\sqrt{349}}{6} $
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