3x2-3x+8x-8=540

Solution for 3x2-3x+8x-8=540 equation:

3x^2-3x+8x-8=540

We move all terms to the left:

3x^2-3x+8x-8-(540)=0

We add all the numbers together, and all the variables

3x^2+5x-548=0

a = 3; b = 5; c = -548;
Δ = b2-4ac
Δ = 52-4·3·(-548)
Δ = 6601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{6601}}{2*3}=\frac{-5-\sqrt{6601}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{6601}}{2*3}=\frac{-5+\sqrt{6601}}{6}
$