3x2-3x-84=0

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Solution for 3x2-3x-84=0 equation:



3x^2-3x-84=0
a = 3; b = -3; c = -84;
Δ = b2-4ac
Δ = -32-4·3·(-84)
Δ = 1017
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1017}=\sqrt{9*113}=\sqrt{9}*\sqrt{113}=3\sqrt{113}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3\sqrt{113}}{2*3}=\frac{3-3\sqrt{113}}{6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3\sqrt{113}}{2*3}=\frac{3+3\sqrt{113}}{6} $

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