3x2-3x-8=0

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Solution for 3x2-3x-8=0 equation: 



3x^2-3x-8=0

a = 3; b = -3; c = -8;
Δ = b2-4ac
Δ = -32-4·3·(-8)
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{105}}{2*3}=\frac{3-\sqrt{105}}{6}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{105}}{2*3}=\frac{3+\sqrt{105}}{6}
$

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