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3x^2-44x+121=0
a = 3; b = -44; c = +121;
Δ = b2-4ac
Δ = -442-4·3·121
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-22}{2*3}=\frac{22}{6} =3+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+22}{2*3}=\frac{66}{6} =11 $
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